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Comment: My octal conversion formula was way wrong. Sorry.
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#Another version doing the octal conversion with arithmetic # faster as it avoids a subshell chr () { printf \\$(($1/64*100+$1%64/8*10+$1%8)) } |
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Some versions avoiding a subshell: {{{ oldchr () { printf \\$(printf '%03o' $1) ;} #posix chr () { set -- $(($1 / 64)) $(($1 % 64)) set -- $1 $(($2 / 8)) $(($2 % 8)) printf \\"${1}${2}${3}" } #bash only chr_bash () { local temp printf -v temp '%03o' $1 printf \\$temp } #test for i in {1..255} ;do [[ "$(oldchr $i)" = "$(chr $i)" ]] || echo $i;done for i in {1..255} ;do [[ "$(oldchr $i)" = "$(chr_bash $i)" ]] || echo $i;done for p in oldchr chr chr_bash; do echo $p:;time for i in {1..4000}; do $p 65 >/dev/null; done; done }}} the timings: {{{ $ bash chr oldchr: real 0m14.350s user 0m5.004s sys 0m9.248s chr: real 0m0.422s user 0m0.059s sys 0m0.216s chr_bash: real 0m0.400s user 0m0.042s sys 0m0.189s }}} Yet another version probably faster: {{{ chr () { printf \\$(($1/64*100+$1%64/8*10+$1%8)) } }}} |
How do I convert an ASCII character to its decimal (or hexadecimal) value and back?
If you have a known octal or hexadecimal value (at script-writing time), you can just use printf:
# POSIX printf '\x27\047\n'
This prints two literal ' characters (27 is the hexadecimal ASCII value of the character, and 47 is the octal value) and a newline.
If you need to convert characters (or numeric ASCII values) that are not known in advance (i.e., in variables), you can use something a little more complicated:
# POSIX # chr() - converts decimal value to its ASCII character representation # ord() - converts ASCII character to its decimal value chr() { printf \\$(printf '%03o' $1) } #Another version doing the octal conversion with arithmetic # faster as it avoids a subshell chr () { printf \\$(($1/64*100+$1%64/8*10+$1%8)) } ord() { printf '%d' "'$1" } # hex() - converts ASCII character to a hexadecimal value # unhex() - converts a hexadecimal value to an ASCII character hex() { printf '%x' "'$1" } unhex() { printf \\x"$1" } # examples: chr $(ord A) # -> A ord $(chr 65) # -> 65
The ord function above is quite tricky.
Tricky? Rather, it's using a feature that I can't find documented anywhere -- putting a single quote in front of an integer. Neat effect, but how on earth did you find out about it? Source diving? -- GreyCat
It validates The Single Unix Specification: "If the leading character is a single-quote or double-quote, the value shall be the numeric value in the underlying codeset of the character following the single-quote or double-quote." (see printf() to know more) -- mjf