Diff for "BashFAQ/066"

Differences between revisions 3 and 11 (spanning 8 versions)

I want to check if [[ $var == foo || $var == bar || $var == more ]] without repeating $var n times.

The portable solution uses case:

   # Bourne
   case "$var" in
      foo|bar|more) ... ;;
   esac

In Bash and ksh, Extended globs can also do this within a [[ command:

   # bash/ksh -- ksh does not need the shopt
   shopt -s extglob
   if [[ $var = @(foo|bar|more) ]]; then
      ...
   fi

-  ⇤ ← Revision 3 as of 2007-05-24 15:17:19 → 
  Size: 496
  Editor: GreyCat
  Comment: =~ example was wrong.  very wrong.  and is still mostly wrong.
+   ← Revision 11 as of 2012-04-29 23:44:04 → ⇥
  Size: 487
  Editor: ormaaj
  Comment: rm old comments, rm regex examples because they're stupid and pointless, add category
-Deletions are marked like this.
+Additions are marked like this.
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-[[Anchor(faq66)]]
+<<Anchor(faq66)>>
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+The portable solution uses `case`:
-Line 4:
+Line 5:
-Here's a portable solution:
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-   case $var in
+   # Bourne
   case "$var" in
-Line 11:
+Line 12:
-And here's one that uses `=~` (which requires bash 3.0 or higher).  This '''only works in bash 3.1''', not in bash 3.2 (and is untested in 3.0):
+In Bash and ksh, [[glob|Extended globs]] can also do this within a `[[` command:
-Line 13:
+Line 14:
-   if [[ $var =~ '^(foo|bar|more)$' ]]; then
+   # bash/ksh -- ksh does not need the shopt
   shopt -s extglob
   if [[ $var = @(foo|bar|more) ]]; then
-Line 18:
+Line 21:
-I'd just stick with the `case`, myself. --GreyCat
+----
CategoryShell