Differences between revisions 1 and 12 (spanning 11 versions)
Revision 1 as of 2007-05-03 00:00:48
Size: 191
Editor: redondos
Comment:
Revision 12 as of 2013-01-03 17:46:44
Size: 838
Editor: static-74-106-235-64
Comment:
Deletions are marked like this. Additions are marked like this.
Line 1: Line 1:
[[Anchor(faq66)]]
== I want to check if [[ $var == foo || $var == bar || $var = more ]] without repeating $var n times. ==
<<Anchor(faq66)>>
== I want to check if [[ $var == foo || $var == bar || $var == more ]] without repeating $var n times. ==
The portable solution uses `case`:
Line 5: Line 6:
   case $var in    # Bourne
case "$var" in
Line 9: Line 11:

In Bash and ksh, [[glob|Extended globs]] can also do this within a `[[` command:
{{{
   # bash/ksh -- ksh does not need the shopt
   shopt -s extglob
   if [[ $var = @(foo|bar|more) ]]; then
      ...
   fi
}}}

Alternatively, the "inarray" function could be used:
{{{
   # usage: inarray NEEDLE HAYSTACK ...
   # returns 0 if NEEDLE is in HAYSTACK, otherwise 1.
   inarray() {
     local n=$1 h
     shift

     for n; do
       [[ $n = "$h" ]] && return
     done
     return 1
   }

   if inarray $var foo bar more; then
     ...
   fi
}}}

----
CategoryShell

I want to check if [[ $var == foo || $var == bar || $var == more ]] without repeating $var n times.

The portable solution uses case:

   # Bourne
   case "$var" in
      foo|bar|more) ... ;;
   esac

In Bash and ksh, Extended globs can also do this within a [[ command:

   # bash/ksh -- ksh does not need the shopt
   shopt -s extglob
   if [[ $var = @(foo|bar|more) ]]; then
      ...
   fi

Alternatively, the "inarray" function could be used:

   # usage: inarray NEEDLE HAYSTACK ...
   # returns 0 if NEEDLE is in HAYSTACK, otherwise 1.
   inarray() {
     local n=$1 h
     shift

     for n; do
       [[ $n = "$h" ]] && return
     done
     return 1
   }

   if inarray $var foo bar more; then
     ...
   fi


CategoryShell

BashFAQ/066 (last edited 2015-06-20 07:58:04 by ormaaj)