1055
Comment: ok for $file, but $x and $y are supposed to be bash parameters
|
1319
added simpler head|tail alternative for multiple lines
|
Deletions are marked like this. | Additions are marked like this. |
Line 1: | Line 1: |
[[Anchor(faq11)]] | <<Anchor(faq11)>> |
Line 4: | Line 4: |
Line 22: | Line 23: |
Another approach, using ["AWK"]: | Another approach, using [[AWK]]: |
Line 30: | Line 31: |
x=3 y=4; | x=3 y=4 |
Line 33: | Line 34: |
head -n $y "$file" | tail -n +$x # even simpler | |
Line 36: | Line 38: |
Using cat(1) (and grep(1) (and cut(1))): | === Note === In most cases, you should sanitize your variable n to be sure, that it's not containing any of non-digits, before feeding it to sed or awk. You can do it with such simple code: {{{ # Bash n=${n//[!0-9]/} |
Line 38: | Line 44: |
{{{ cat -n file | grep '^ *<number of line>' | cut -f 2 |
# POSIX n=$(printf "%s" "$n"|tr -cd '0-9') |
Line 41: | Line 47: |
---- CategoryShell |
How can I print the n'th line of a file?
The dirty (but not quick) way would be:
sed -n ${n}p "$file"
but this reads the whole input file, even if you only wanted the third line.
This one avoids that problem:
sed -n "$n{p;q;}" "$file"
At line $n the command "p" is run, printing it, with a "q" afterwards: quit the program.
Another way, more obvious to some, is to grab the last line from a listing of the first n lines:
head -n $n $file | tail -n 1
Another approach, using AWK:
awk "NR==$n{print;exit}" file
If you want more than one line, it's pretty easy to adapt any of the previous methods:
x=3 y=4 sed -n "$x,${y}p;${y}q;" "$file" # Print lines $x to $y; quit after $y. head -n $y "$file" | tail -n $(($y - $x + 1)) # Same head -n $y "$file" | tail -n +$x # even simpler awk "NR>=$x{print} NR==$y{exit}" "$file" # Same
Note
In most cases, you should sanitize your variable n to be sure, that it's not containing any of non-digits, before feeding it to sed or awk. You can do it with such simple code:
# Bash n=${n//[!0-9]/} # POSIX n=$(printf "%s" "$n"|tr -cd '0-9')