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[[Anchor(faq11)]] | <<Anchor(faq11)>> |
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Another approach, using ["AWK"]: | Another approach, using [[AWK]]: |
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x=3 y=4 | |
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head -n $y "$file" | tail -n $(($y - $x + 1)) # Same awk 'NR>=$x{print} NR==$y{exit}' "$file" # Same |
head -n $y "$file" | tail -n $((y - x + 1)) # Same head -n $y "$file" | tail -n +$x # If your tail supports it awk "NR>=$x{print} NR==$y{exit}" "$file" # Same |
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Using cat(1) (and grep(1) (and cut(1))): | === Note === In most cases, you should sanitize your variable n to be sure, that it's not containing any of non-digits, before feeding it to sed or awk. You can do it with such simple code: {{{ # Bash n=${n//[!0-9]/} |
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{{{ cat -n file | grep '^ *<number of line>' | cut -f 2 |
# POSIX n=$(printf "%s" "$n"|tr -cd '0-9') |
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---- CategoryShell |
How can I print the n'th line of a file?
The dirty (but not quick) way would be:
sed -n ${n}p "$file"
but this reads the whole input file, even if you only wanted the third line.
This one avoids that problem:
sed -n "$n{p;q;}" "$file"
At line $n the command "p" is run, printing it, with a "q" afterwards: quit the program.
Another way, more obvious to some, is to grab the last line from a listing of the first n lines:
head -n $n $file | tail -n 1
Another approach, using AWK:
awk "NR==$n{print;exit}" file
If you want more than one line, it's pretty easy to adapt any of the previous methods:
x=3 y=4 sed -n "$x,${y}p;${y}q;" "$file" # Print lines $x to $y; quit after $y. head -n $y "$file" | tail -n $((y - x + 1)) # Same head -n $y "$file" | tail -n +$x # If your tail supports it awk "NR>=$x{print} NR==$y{exit}" "$file" # Same
Note
In most cases, you should sanitize your variable n to be sure, that it's not containing any of non-digits, before feeding it to sed or awk. You can do it with such simple code:
# Bash n=${n//[!0-9]/} # POSIX n=$(printf "%s" "$n"|tr -cd '0-9')