Diff for "BashFAQ/011"

Differences between revisions 30 and 34 (spanning 4 versions)

How can I print the n'th line of a file?

One dirty (but not quick) way is:

   1 sed -n "${n}p" "$file"

But this reads the entire file even if only the third line is desired, which can be avoided by using the q command to quit on line $n, and deleting all other lines with the d command:

   1 sed "${n}q;d" "$file"

Another method is to grab the last line from a listing of the first n lines. However, if the file has less than n lines, this will output the last line, unlike the other approaches which will have empty output.

   1 head -n "$n" "$file" | tail -n 1

Another approach, using AWK:

   1 awk "NR==$n{print;exit}" "$file"

If more than one line is needed, it's easy to adapt any of the previous methods:

   1 x=3 y=4
   2 sed -n "$x,${y}p;${y}q;" "$file"                # Print lines $x to $y; quit after $y.
   3 head -n "$y" "$file" | tail -n "$((y - x + 1))"   # Same
   4 head -n "$y" "$file" | tail -n "+$x"            # If your tail supports it
   5 awk "NR>=$x{print} NR==$y{exit}" "$file"        # Same

Or a counter with a simple read loop:

   1 # Bash/ksh
   2 m=0
   3 while ((m++ < n)) && read -r _; do
   4     :
   5 done
   6 
   7 head -n 1

To read into a variable, it is preferable to use read or mapfile rather than an external utility. More than one line can be read into the given array variable or the default array MAPFILE by adjusting the argument to mapfile's -n option:

   1 # Bash4
   2 mapfile -ts "$((n - 1))" -n 1 x <"$file"
   3 printf '%s\n' "$x"

-  ⇤ ← Revision 30 as of 2016-06-16 01:20:29 → 
  Size: 1932
  Editor: tor-exit
  Comment: using ; as a command delimiter within the { command is specified as an optional extension by posix, and is not required.
+   ← Revision 34 as of 2016-09-22 07:21:05 → ⇥
  Size: 1790
  Editor: geirha
  Comment: rewording previous edit
-Deletions are marked like this.
+Additions are marked like this.
 Line 15:
-Another method is to grab the last line from a listing of the first `n` lines:
+Another method is to grab the last line from a listing of the first `n` lines. However, if the file has less than `n` lines, this will output the last line, unlike the other approaches which will have empty output.
 Line 32:
-head -n "$y" "$file" | tail -n $((y - x + 1))   # Same
+head -n "$y" "$file" | tail -n "$((y - x + 1))"   # Same
 Line 35:
-}}}

In Bash 4, `mapfile` can be used similarly to `head` while avoiding buffering issues in the event input is a pipe, because it guarantees the [[ FileDescriptor|fd ]] will be seeked to where you left it:

{{{#!highlight bash
# Bash4
{ mapfile -n "$n"; head -n 1; } <"$file"
-Line 60:
+Line 53:
-mapfile -ts $((n-1)) -n 1 x <"$file"
+mapfile -ts "$((n - 1))" -n 1 x <"$file"

Diff for "BashFAQ/011"

How can I print the n'th line of a file?

See Also