Diff for "BashFAQ/011"

Differences between revisions 27 and 37 (spanning 10 versions)

How can I print the n'th line of a file?

One dirty (but not quick) way is:

   1 sed -n "${n}p" "$file"

But this reads the entire file even if only the third line is desired, which can be avoided by using the q command to quit on line $n, and deleting all other lines with the d command:

   1 sed "${n}q;d" "$file"

There is yet another simple way of printing only the line you want using sed. The -n option will not print anything unless p flag is explicitly specified. For example to print the 4th line in a file use.

   1 sed -n "4p" "$file"

Another method is to grab lines starting at n, then get the first line of that.

   1 tail -n "+$n" "$file" | head -n 1

Another approach, using AWK:

   1 awk "NR==$n{print;exit}" "$file"

If more than one line is needed, it's easy to adapt any of the previous methods:

   1 x=3 y=4
   2 sed -n "$x,${y}p;${y}q;" "$file"                # Print lines $x to $y; quit after $y.
   3 head -n "$y" "$file" | tail -n "$((y - x + 1))"   # Same
   4 head -n "$y" "$file" | tail -n "+$x"            # If your tail supports it
   5 awk "NR>=$x{print} NR==$y{exit}" "$file"        # Same

Or a counter with a simple read loop:

   1 # Bash/ksh
   2 m=0
   3 while ((m++ < n)) && read -r _; do
   4     :
   5 done
   6 
   7 head -n 1

To read into a variable, it is preferable to use read or mapfile rather than an external utility. More than one line can be read into the given array variable or the default array MAPFILE by adjusting the argument to mapfile's -n option:

   1 # Bash4
   2 mapfile -ts "$((n - 1))" -n 1 x <"$file"
   3 printf '%s\n' "$x"

-  ⇤ ← Revision 27 as of 2012-02-27 02:27:07 → 
  Size: 1538
  Editor: ormaaj
  Comment: Agree with Lhunath - rm useless note. Fix writing style.
+   ← Revision 37 as of 2018-12-21 20:48:17 → ⇥
  Size: 1920
  Editor: Valentin Bajrami
  Comment:
-Deletions are marked like this.
+Additions are marked like this.
 Line 5:
-{{{
    sed -n ${n}p "$file"
+{{{#!highlight bash
sed -n "${n}p" "$file"
 Line 8:
-But this reads the entire file even if only the third line is desired, which can be avoided by printing line {{{$n}}} using the "p" command, followed by a "q" to exit the script:
-Line 10:
+Line 9:
-{{{
    sed -n "$n{p;q;}" "$file"
+But this reads the entire file even if only the third line is desired, which can be avoided by using the `q` command to quit on line `$n`, and deleting all other lines with the `d` command:

{{{#!highlight bash
sed "${n}q;d" "$file"
-Line 13:
+Line 14:
-Another method is to grab the last line from a listing of the first {{{n}}} lines:
 Line 15:
-{{{
   head -n $n $file | tail -n 1
+There is yet another simple way of printing only the line you want using `sed`. The `-n` option will not print anything unless `p` flag is explicitly specified. For example to print the 4th line in a file use.

{{{#!highlight bash
sed -n "4p" "$file"
-Line 18:
+Line 20:
+Another method is to grab lines starting at `n`, then get the first line of that.

{{{#!highlight bash
tail -n "+$n" "$file" | head -n 1
}}}
-Line 20:
+Line 29:
-{{{
   awk "NR==$n{print;exit}" file
+{{{#!highlight bash
awk "NR==$n{print;exit}" "$file"
-Line 23:
+Line 32:
-Line 25:
+Line 35:
-{{{
   x=3 y=4
   sed -n "$x,${y}p;${y}q;" "$file"                # Print lines $x to $y; quit after $y.
   head -n $y "$file" | tail -n $((y - x + 1))     # Same
   head -n $y "$file" | tail -n +$x                # If your tail supports it
   awk "NR>=$x{print} NR==$y{exit}" "$file"        # Same
+{{{#!highlight bash
x=3 y=4
sed -n "$x,${y}p;${y}q;" "$file"                # Print lines $x to $y; quit after $y.
head -n "$y" "$file" | tail -n "$((y - x + 1))"   # Same
head -n "$y" "$file" | tail -n "+$x"            # If your tail supports it
awk "NR>=$x{print} NR==$y{exit}" "$file"        # Same
-Line 32:
+Line 42:
-In Bash 4, a pure-bash solution can be achieved succinctly using the {{{mapfile}}} builtin. More than one line can be read into the array {{{MAPFILE}}} by adjusting the argument to mapfile's -n option:
-Line 34:
+Line 43:
-{{{
   mapfile -ts $((n-1)) -n 1 < "$file"
   echo "${MAPFILE[0]}"
+Or a counter with a simple `read` loop:

{{{#!highlight bash
# Bash/ksh
m=0
while ((m++ < n)) && read -r _; do
    :
done

head -n 1
-Line 38:
+Line 54:
-{{{mapfile}}} can also be used similarly to {{{head}}} while avoiding buffering issues in the event input is a pipe:
-Line 40:
+Line 55:
-{{{
   { mapfile -n $n; head -n 1; } <"$file"
+To read into a variable, it is preferable to use `read` or `mapfile` rather than an external utility. More than one line can be read into the given array variable or the default array `MAPFILE` by adjusting the argument to mapfile's -n option:

{{{#!highlight bash
# Bash4
mapfile -ts "$((n - 1))" -n 1 x <"$file"
printf '%s\n' "$x"

Diff for "BashFAQ/011"

How can I print the n'th line of a file?

See Also