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Comment:
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Switch order of head and tail to avoid problems if file contains less than n lines. Also requires less data to be copied.
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= How can I print the n'th line of a file? = The dirty (but not quick) way would be: |
== How can I print the n'th line of a file? == One dirty (but not quick) way is: |
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{{{ sed -n ${n}p "$file" |
{{{#!highlight bash sed -n "${n}p" "$file" |
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but this reads the whole input file, even if you only wanted the third line. | |
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This one avoids that problem: | But this reads the entire file even if only the third line is desired, which can be avoided by using the `q` command to quit on line `$n`, and deleting all other lines with the `d` command: |
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{{{ sed -n "$n{p;q;}" "$file" |
{{{#!highlight bash sed "${n}q;d" "$file" |
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At line $n the command "p" is run, printing it, with a "q" afterwards: quit the program. | |
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Another way, more obvious to some, is to grab the last line from a listing of the first ''n'' lines: | Another method is to grab lines starting at `n`, then get the first line of that. |
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{{{ head -n $n $file | tail -n 1 |
{{{#!highlight bash tail -n "+$n" "$file" | head -n 1 |
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{{{ awk "NR==$n{print;exit}" file |
{{{#!highlight bash awk "NR==$n{print;exit}" "$file" |
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If you want more than one line, it's pretty easy to adapt any of the previous methods: | |
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{{{ x=3 y=4 sed -n "$x,${y}p;${y}q;" "$file" # Print lines $x to $y; quit after $y. head -n $y "$file" | tail -n $((y - x + 1)) # Same head -n $y "$file" | tail -n +$x # If your tail supports it awk "NR>=$x{print} NR==$y{exit}" "$file" # Same |
If more than one line is needed, it's easy to adapt any of the previous methods: {{{#!highlight bash x=3 y=4 sed -n "$x,${y}p;${y}q;" "$file" # Print lines $x to $y; quit after $y. head -n "$y" "$file" | tail -n "$((y - x + 1))" # Same head -n "$y" "$file" | tail -n "+$x" # If your tail supports it awk "NR>=$x{print} NR==$y{exit}" "$file" # Same |
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In Bash 4, this can also be done with mapfile builtin: | |
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{{{ mapfile -ts $((n-1)) -n 1 echo "$MAPFILE" |
Or a counter with a simple `read` loop: {{{#!highlight bash # Bash/ksh m=0 while ((m++ < n)) && read -r _; do : done head -n 1 |
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By changing the value of argument for -n, you can get more than one line in the array MAPFILE. | |
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=== Note === In most cases, you should sanitize your variable n to be sure, that it's not containing any of non-digits, before feeding it to sed or awk. You can do it with such simple code: |
To read into a variable, it is preferable to use `read` or `mapfile` rather than an external utility. More than one line can be read into the given array variable or the default array `MAPFILE` by adjusting the argument to mapfile's -n option: |
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{{{ # Bash n=${n//[!0-9]/} |
{{{#!highlight bash # Bash4 mapfile -ts "$((n - 1))" -n 1 x <"$file" printf '%s\n' "$x" }}} |
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# POSIX n=$(printf "%s" "$n"|tr -cd '0-9') }}} . One can argue that an `n` value of `Five brown horses with 3 feet and 9 little piggies.` should yield an error rather than silently behave as though it was really `39`. If you want to code safe, quote your expansions and be done with it. --[[Lhunath]] |
=== See Also === * [[BashFAQ/001]] * http://wiki.bash-hackers.org/commands/builtin/mapfile |
How can I print the n'th line of a file?
One dirty (but not quick) way is:
1 sed -n "${n}p" "$file"
But this reads the entire file even if only the third line is desired, which can be avoided by using the q command to quit on line $n, and deleting all other lines with the d command:
1 sed "${n}q;d" "$file"
Another method is to grab lines starting at n, then get the first line of that.
1 tail -n "+$n" "$file" | head -n 1
Another approach, using AWK:
1 awk "NR==$n{print;exit}" "$file"
If more than one line is needed, it's easy to adapt any of the previous methods:
Or a counter with a simple read loop:
To read into a variable, it is preferable to use read or mapfile rather than an external utility. More than one line can be read into the given array variable or the default array MAPFILE by adjusting the argument to mapfile's -n option: