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The dirty (but not quick) way would be: One dirty (but not quick) way is:
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{{{
    sed -n ${n}p "$file"
{{{#!highlight bash
sed -n "${n}p" "$file"
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but this reads the whole input file, even if you only wanted the third line. But this reads the entire file even if only the third line is desired, which can be avoided by using the `q` command to quit on line `$n`, and deleting all other lines with the `d` command:
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This one avoids that problem:
{{{
    sed -n "$n{p;q;}" "$file"
{{{#!highlight bash
sed "${n}q;d" "$file"
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At line $n the command "p" is run, printing it, with a "q" afterwards: quit the program. Another method is to grab the last line from a listing of the first `n` lines:
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Another way, more obvious to some, is to grab the last line from a listing of the first ''n'' lines:
{{{
   head -n $n $file | tail -n 1
{{{#!highlight bash
head -n "$n" "$file" | tail -n 1
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{{{
   awk "NR==$n{print;exit}" file

{{{#!highlight bash
awk "NR==$n{print;exit}" "$file"
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If you want more than one line, it's pretty easy to adapt any of the previous methods: If more than one line is needed, it's easy to adapt any of the previous methods:
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{{{
   
x=3 y=4
   sed -n "$x,${y}p;${y}q;" "$file" # Print lines $x to $y; quit after $y.
   head -n $y "$file" | tail -n $(($y - $x + 1)) # Same
   awk "NR>=$x{print} NR==$y{exit}" "$file" # Same
{{{#!highlight bash
x=3 y=4
sed -n "$x,${y}p;${y}q;" "$file" # Print lines $x to $y; quit after $y.
head -n "$y" "$file" | tail -n "$((y - x + 1))" # Same
head -n "$y" "$file" | tail -n "+$x" # If your tail supports it
awk "NR>=$x{print} NR==$y{exit}" "$file" # Same
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Or a counter with a simple `read` loop:

{{{#!highlight bash
# Bash/ksh
m=0
while ((m++ < n)) && read -r _; do
    :
done

head -n 1
}}}

To read into a variable, it is preferable to use `read` or `mapfile` rather than an external utility. More than one line can be read into the given array variable or the default array `MAPFILE` by adjusting the argument to mapfile's -n option:

{{{#!highlight bash
# Bash4
mapfile -ts "$((n - 1))" -n 1 x <"$file"
printf '%s\n' "$x"
}}}

=== See Also ===
 * [[BashFAQ/001]]
 * http://wiki.bash-hackers.org/commands/builtin/mapfile

How can I print the n'th line of a file?

One dirty (but not quick) way is:

   1 sed -n "${n}p" "$file"

But this reads the entire file even if only the third line is desired, which can be avoided by using the q command to quit on line $n, and deleting all other lines with the d command:

   1 sed "${n}q;d" "$file"

Another method is to grab the last line from a listing of the first n lines:

   1 head -n "$n" "$file" | tail -n 1

Another approach, using AWK:

   1 awk "NR==$n{print;exit}" "$file"

If more than one line is needed, it's easy to adapt any of the previous methods:

   1 x=3 y=4
   2 sed -n "$x,${y}p;${y}q;" "$file"                # Print lines $x to $y; quit after $y.
   3 head -n "$y" "$file" | tail -n "$((y - x + 1))"   # Same
   4 head -n "$y" "$file" | tail -n "+$x"            # If your tail supports it
   5 awk "NR>=$x{print} NR==$y{exit}" "$file"        # Same

Or a counter with a simple read loop:

   1 # Bash/ksh
   2 m=0
   3 while ((m++ < n)) && read -r _; do
   4     :
   5 done
   6 
   7 head -n 1

To read into a variable, it is preferable to use read or mapfile rather than an external utility. More than one line can be read into the given array variable or the default array MAPFILE by adjusting the argument to mapfile's -n option:

   1 # Bash4
   2 mapfile -ts "$((n - 1))" -n 1 x <"$file"
   3 printf '%s\n' "$x"

See Also


CategoryShell

BashFAQ/011 (last edited 2020-05-07 08:35:17 by intranet)