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Comment: first-line; remove extraneous ;
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note about the head|tail approach
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Deletions are marked like this. | Additions are marked like this. |
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The dirty (but not quick) way would be: | One dirty (but not quick) way is: |
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{{{ sed -n ${n}p "$file" |
{{{#!highlight bash sed -n "${n}p" "$file" |
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but this reads the whole input file, even if you only wanted the third line. | But this reads the entire file even if only the third line is desired, which can be avoided by using the `q` command to quit on line `$n`, and deleting all other lines with the `d` command: |
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This one avoids that problem: {{{ sed -n "$n{p;q;}" "$file" |
{{{#!highlight bash sed "${n}q;d" "$file" |
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At line $n the command "p" is run, printing it, with a "q" afterwards: quit the program. | Another method is to grab the last line from a listing of the first `n` lines. However, this is only applicable if you know the file has at least `n` lines. |
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Another way, more obvious to some, is to grab the last line from a listing of the first ''n'' lines: {{{ head -n $n $file | tail -n 1 |
{{{#!highlight bash head -n "$n" "$file" | tail -n 1 |
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{{{ awk "NR==$n{print;exit}" file |
{{{#!highlight bash awk "NR==$n{print;exit}" "$file" |
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If you want more than one line, it's pretty easy to adapt any of the previous methods: | If more than one line is needed, it's easy to adapt any of the previous methods: |
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{{{ x=3 y=4 sed -n "$x,${y}p;${y}q;" "$file" # Print lines $x to $y; quit after $y. head -n $y "$file" | tail -n $(($y - $x + 1)) # Same awk "NR>=$x{print} NR==$y{exit}" "$file" # Same |
{{{#!highlight bash x=3 y=4 sed -n "$x,${y}p;${y}q;" "$file" # Print lines $x to $y; quit after $y. head -n "$y" "$file" | tail -n "$((y - x + 1))" # Same head -n "$y" "$file" | tail -n "+$x" # If your tail supports it awk "NR>=$x{print} NR==$y{exit}" "$file" # Same |
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Or a counter with a simple `read` loop: {{{#!highlight bash # Bash/ksh m=0 while ((m++ < n)) && read -r _; do : done head -n 1 }}} To read into a variable, it is preferable to use `read` or `mapfile` rather than an external utility. More than one line can be read into the given array variable or the default array `MAPFILE` by adjusting the argument to mapfile's -n option: {{{#!highlight bash # Bash4 mapfile -ts "$((n - 1))" -n 1 x <"$file" printf '%s\n' "$x" }}} === See Also === * [[BashFAQ/001]] * http://wiki.bash-hackers.org/commands/builtin/mapfile ---- CategoryShell |
How can I print the n'th line of a file?
One dirty (but not quick) way is:
1 sed -n "${n}p" "$file"
But this reads the entire file even if only the third line is desired, which can be avoided by using the q command to quit on line $n, and deleting all other lines with the d command:
1 sed "${n}q;d" "$file"
Another method is to grab the last line from a listing of the first n lines. However, this is only applicable if you know the file has at least n lines.
1 head -n "$n" "$file" | tail -n 1
Another approach, using AWK:
1 awk "NR==$n{print;exit}" "$file"
If more than one line is needed, it's easy to adapt any of the previous methods:
Or a counter with a simple read loop:
To read into a variable, it is preferable to use read or mapfile rather than an external utility. More than one line can be read into the given array variable or the default array MAPFILE by adjusting the argument to mapfile's -n option: