Diff for "BashFAQ/005"

Anchor(faq5)

How can I use array variables?

BASH and KornShell have one-dimensional arrays indexed by a numerical expression, e.g.

•  # Bash
   host[0]="micky"
   host[1]="minnie"
   host[2]="goofy"
   i=0
   while (( $i < ${#host[@]} ))
   do
       echo "host number $i is ${host[i++]}"
   done

The indexing always begins with 0.

The awkward expression ${#host[@]} returns the number of elements for the array host. Also noteworthy for BASH is the fact that inside the square brackets, i++ works as a C programmer would expect. The square brackets in an array reference force an ArithmeticExpression. (That shortcut does not work in ksh88.)

It's possible to assign multiple values to an array at once, but the syntax differs across shells.

•  # Bash
   array=(one two three four)
  
   # Korn
   set -A array -- one two three four

Bash also lets you initialize an array using a [:glob:]:

•  # Bash
   oggs=(*.ogg)

Using array elements en masse is one of the key features. In exactly the same way that "$@" is expanded for positional parameters, "${arr[@]}" is expanded to a list of words, one array element per word. For example,

•  # Korn/Bash
   for x in "${arr[@]}"; do
     echo "next element is '$x'"
   done

This works even if the elements contain whitespace. You always end up with the same number of words as you have array elements.

If one simply wants to dump the full array, one element per line, this is the simplest approach:

•  # Bash/ksh
   printf "%s\n" "${arr[@]}"

For more complex array-dumping, "${arr[*]}" will cause the elements to be concatenated together, with the first character of IFS (or a space if IFS isn't set) between them. As it happens, "$*" is expanded the same way for positional parameters.

•  # Bash
   arr=(x y z)
   IFS=/; echo "${arr[*]}"; unset IFS
   # prints x/y/z

BASH and Korn shell arrays are also sparse. Elements may be added and deleted out of sequence.

•  # Bash
   arr=(0 1 2 3)
   arr[42]="what was the question?"
   unset arr[2]
   echo "${arr[*]}"
   # prints 0 1 3 what was the question?

BASH 3.0 added the ability to retrieve the list of index values in an array, rather than just iterating over the elements:

•  # Bash 3.0 or higher
   echo ${!arr[*]}
   # using the previous array, prints 0 1 3 42

Bash's [:BashFAQ/073:Parameter Expansions] may be performed on array elements en masse as well:

•  # Bash
   arr=(abc def ghi jkl)
   echo "${arr[@]#?}"          # prints bc ef hi kl
   echo "${arr[@]/[aeiou]/}"   # prints bc df gh jkl

Parameter Expansion can also be used to extract elements from an array:

•  # Bash
   echo "${arr[@]:1:3}"        # three elements starting at #1 (second element)
   echo "${arr[@]:(-2)}"       # last two elements
   echo "${@:(-1)}"            # last positional parameter
   echo "${@:(-2):1}"          # second-to-last positional parameter

The @ array (the array of positional parameters) can be used just like any regularly named array.

If you wish to append data to an existing array, there are several approaches. The most flexible is to keep a separate index variable:

•  # Bash/ksh93
   arr[i++]="new item"

If you don't want to keep an index variable, but you happen to know that your array is not sparse, then you can use the highest existing index:

•  # Bash/ksh
   # This will FAIL if the array has holes (is sparse).
   arr[${#arr[*]}]="new item"

If you don't know whether your array is sparse or not, but you don't mind re-indexing the entire array (and also being very slow), then you can use:

•  # Bash
   arr=("${arr[@]}" "new item")
  
   # Ksh
   set -A arr -- "${arr[@]}" "new item"

If you're in bash 3.1 or higher, then you can use the += operator:

•  # Bash 3.1
   arr+=("new item")

For examples of loading data into arrays, see [:BashFAQ/001:FAQ #1]. For examples of using arrays to hold complex shell commands, see [:BashFAQ/050:FAQ #50] and [:BashFAQ/040:FAQ #40].