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For simple variables, you can trim whitespace (or other characters) using this trick: {{{ # POSIX junk="${var##*[! ]}" # match prefixed spaces var="${var%%$junk}" # trim the match junk="${var%%[! ]*}" # match affixed spaces var="${var##$junk}" # trim the match }}} Bash can do the same thing, but without the need for a throw-away variable, by using [[glob|extglob]]'s more advanced pattern matching: {{{ # Bash shopt -s extglob var="${var##*( )}" # trim the left var="${var%%*( )}" # trim the right }}} |
How can I trim leading/trailing white space from one of my variables?
There are a few ways to do this. Some involve special tricks that only work with whitespace. Others are more general, and can be used to strip leading zeroes, etc.
For simple variables, you can trim whitespace (or other characters) using this trick:
# POSIX junk="${var##*[! ]}" # match prefixed spaces var="${var%%$junk}" # trim the match junk="${var%%[! ]*}" # match affixed spaces var="${var##$junk}" # trim the match
Bash can do the same thing, but without the need for a throw-away variable, by using extglob's more advanced pattern matching:
# Bash shopt -s extglob var="${var##*( )}" # trim the left var="${var%%*( )}" # trim the right
Here's one that only works for whitespace. It relies on the fact that read strips all leading and trailing whitespace when IFS isn't set:
# POSIX, but fails if the variable contains newlines read -r var << EOF $var EOF
Bash can do something similar with a "here string":
# Bash read -rd '' x <<< "$x"
Using an empty string as a delimiter means the read consumes the whole string, as NUL is used. (Remember: BASH only does C-string variables.) This is entirely safe for any text, including newlines.
Here's a solution using extglob together with parameter expansion:
# Bash shopt -s extglob x=${x##+([[:space:]])} x=${x%%+([[:space:]])}
This also works in KornShell, without needing the explicit extglob setting:
# ksh x=${x##+([[:space:]])} x=${x%%+([[:space:]])}
This solution isn't restricted to whitespace like the first few were. You can remove leading zeroes as well:
# Bash shopt -s extglob x=${x##+(0)}
Another way to remove leading zeroes from a number in bash is to treat it as an integer, in a math context:
# Bash x=$((10#$x)) # However, this fails if x contains anything other than digits.
If you need to remove leading zeroes in a POSIX shell, you can use a loop:
# POSIX while true; do case "$var" in 0*) var=${var#0};; *) break;; esac done
Or this trick (covered in more detail in FAQ #100):
# POSIX zeroes=${var%%[!0]*} var=${var#$zeroes}
There are many, many other ways to do this, using sed for instance:
# POSIX, suppress the trailing and leading whitespace on every line x=$(echo "$x" | sed -e 's/^[[:space:]]*//' -e 's/[[:space:]]*$//')
Solutions based on external programs like sed are better suited to trimming large files, rather than shell variables.