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Revision 11 as of 2008-11-22 14:08:55
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Revision 12 as of 2009-05-10 03:42:31
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Comment: igli: *sigh* BASH handles strings fine. m00 gc ;-)
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There are a few ways to do this:  There are a few ways to do this:
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   $var 
   EOF 
   $var
   EOF
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One can also achieve in bash using a herestring The easiest and cleanest way is with a bash herestring:
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   # Bash still fails if the variable contains a newline.
   read -r x <<< "$x"
   read -rd '' x <<< "$x"
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Using an empty string as a delimiter means the read consumes the whole string, as NUL is used. (Remember: BASH only does C-string variables.) This is entirely safe for any text, including newlines.
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(note: using IFS=$' \t' read -d "" -r x partially fix the "problem" of the newlines but adds a trailing \n)

There's also a solution using [[glob|extglob]]:
There's also a solution using [[glob|extglob]] which shows how you can use it in parameter expansion:
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There are many, many other ways to do this, using sed for instance:   There are many, many other ways to do this, using sed for instance:
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These are not necessarily the best, but they're known to work.

How can I trim leading/trailing white space from one of my variables?

There are a few ways to do this:

   #POSIX, but fails if the variable contains newlines
   read -r var << EOF
   $var
   EOF

The easiest and cleanest way is with a bash herestring:

   read  -rd '' x <<< "$x"

Using an empty string as a delimiter means the read consumes the whole string, as NUL is used. (Remember: BASH only does C-string variables.) This is entirely safe for any text, including newlines.

There's also a solution using extglob which shows how you can use it in parameter expansion:

   # Bash
   shopt -s extglob
   x=${x##+([[:space:]])} x=${x%%+([[:space:]])}
   shopt -u extglob

This also works in KornShell, without needing the explicit extglob setting:

   # ksh
   x=${x##+([[:space:]])} x=${x%%+([[:space:]])}

There are many, many other ways to do this, using sed for instance:

   # POSIX, suppress the trailing and leading whitespace on every lines
   x=$(echo "$x" | sed -e 's/^[[:space:]]*//' -e 's/[[:space:]]*$//')

BashFAQ/067 (last edited 2018-11-29 15:32:42 by GreyCat)