I want to check if [[ $var == foo || $var == bar || $var == more ]] without repeating $var n times.
The portable solution uses case:
# Bourne case "$var" in foo|bar|more) ... ;; esac
In Bash and ksh, Extended globs can also do this within a [[ command:
# bash/ksh ${BASH_VERSION+shopt -s extglob} if [[ $var == @(foo|bar|more) ]]; then ... fi
Alternatively, you may loop over a list of patterns, checking each individually.
# bash/ksh93/zsh (w/ emulate ksh) # usage: pmatch string pattern [ pattern ... ] function pmatch { ${1+typeset x=}"${1-false}" && while command shift; do [[ $x == $1 ]] && return done 2>/dev/null return 1 } var='foo bar' if pmatch "$var" foo bar baz foo\* blarg; then : ... fi
For logical conjunction (return true if $var matches all patterns), ksh93 can use the & pattern delimiter.
# ksh93 only [[ $var == @(foo&bar&more) ]] && ...
For shells that support only the ksh88 subset (extglob patterns), you may DeMorganify the logic using the negation sub-pattern operator.
# bash/ksh88/etc... ${BASH_VERSION+shopt -s extglob} [[ $var == !(!(foo)|!(bar)|!(more)) ]] && ...
But this is quite unclear and not much shorter than just writing out separate expressions for each pattern.