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Comment: rm old comments, rm regex examples because they're stupid and pointless, add category
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case $var in | # Bourne case "$var" in |
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And here's one that uses `=~` (which requires bash 3.0 or higher): | In Bash and ksh, [[glob|Extended globs]] can also do this within a `[[` command: |
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regex='^(foo|bar|more)$' if [[ $var =~ $regex ]]; then |
# bash/ksh -- ksh does not need the shopt shopt -s extglob if [[ $var = @(foo|bar|more) ]]; then |
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This one '''only works in bash 3.1''' and '''some 3.2 revisions''' (it is untested in 3.0): {{{ if [[ $var =~ '^(foo|bar|more)$' ]]; then ... fi }}} The `=~` operator behavior changes drastically between 3.1 and 3.2, so be careful with it. The above expression is tested to work in bash ''3.1'' and ''3.2.{13,15,17}''; and it doesn't work in ''3.2.0''. Please also note that the regexp does not need to be quoted in the 3.2 revisions where it works. --[[redondos]] Normally I would never advocate [[BashFAQ/050|sticking code into a variable]] and attempting to use it -- lots of people have ''enormous'' trouble because they try to do that. In the case of `=~`, though, it seems to be required. Personally, I'd just stick with the `case`. --GreyCat The regexp works as long as it is quoted with bash version ''3.00.15(1)-release'' on CentOS4/RHEL4. I didn't bother checking whether bash is a patched version or not in CentOS4/RHEL4. --ellingsw |
---- CategoryShell |
I want to check if [[ $var == foo || $var == bar || $var == more ]] without repeating $var n times.
The portable solution uses case:
# Bourne case "$var" in foo|bar|more) ... ;; esac
In Bash and ksh, Extended globs can also do this within a [[ command:
# bash/ksh -- ksh does not need the shopt shopt -s extglob if [[ $var = @(foo|bar|more) ]]; then ... fi