Diff for "BashFAQ/066"

Differences between revisions 2 and 12 (spanning 10 versions)

I want to check if [[ $var == foo || $var == bar || $var == more ]] without repeating $var n times.

The portable solution uses case:

   # Bourne
   case "$var" in
      foo|bar|more) ... ;;
   esac

In Bash and ksh, Extended globs can also do this within a [[ command:

   # bash/ksh -- ksh does not need the shopt
   shopt -s extglob
   if [[ $var = @(foo|bar|more) ]]; then
      ...
   fi

Alternatively, the "inarray" function could be used:

   # usage: inarray NEEDLE HAYSTACK ...
   # returns 0 if NEEDLE is in HAYSTACK, otherwise 1.
   inarray() {
     local n=$1 h
     shift

     for n; do
       [[ $n = "$h" ]] && return
     done
     return 1
   }

   if inarray $var foo bar more; then
     ...
   fi

CategoryShell

-  ⇤ ← Revision 2 as of 2007-05-24 14:21:15 → 
  Size: 323
  Editor: redondos
  Comment:
+   ← Revision 12 as of 2013-01-03 17:46:44 → ⇥
  Size: 838
  Editor: static-74-106-235-64
  Comment:
-Deletions are marked like this.
+Additions are marked like this.
 Line 1:
-[[Anchor(faq66)]]
+<<Anchor(faq66)>>
 Line 3:
+The portable solution uses `case`:
-Line 4:
+Line 5:
-Here's a portable solution:
 Line 6:
-   case $var in
+   # Bourne
   case "$var" in
-Line 11:
+Line 12:
-And here's one that uses '[[':
+In Bash and ksh, [[glob|Extended globs]] can also do this within a `[[` command:
-Line 13:
+Line 14:
-   if [[ $var =~ foo|bar|more ]]; then
+   # bash/ksh -- ksh does not need the shopt
   shopt -s extglob
   if [[ $var = @(foo|bar|more) ]]; then
-Line 17:
+Line 20:
+Alternatively, the "inarray" function could be used:
{{{
   # usage: inarray NEEDLE HAYSTACK ...
   # returns 0 if NEEDLE is in HAYSTACK, otherwise 1.
   inarray() {
     local n=$1 h
     shift

     for n; do
       [[ $n = "$h" ]] && return
     done
     return 1
   }

   if inarray $var foo bar more; then
     ...
   fi
}}}

----
CategoryShell