Diff for "BashFAQ/066"

Differences between revisions 11 and 12

I want to check if [[ $var == foo || $var == bar || $var == more ]] without repeating $var n times.

The portable solution uses case:

   # Bourne
   case "$var" in
      foo|bar|more) ... ;;
   esac

In Bash and ksh, Extended globs can also do this within a [[ command:

   # bash/ksh -- ksh does not need the shopt
   shopt -s extglob
   if [[ $var = @(foo|bar|more) ]]; then
      ...
   fi

Alternatively, the "inarray" function could be used:

   # usage: inarray NEEDLE HAYSTACK ...
   # returns 0 if NEEDLE is in HAYSTACK, otherwise 1.
   inarray() {
     local n=$1 h
     shift

     for n; do
       [[ $n = "$h" ]] && return
     done
     return 1
   }

   if inarray $var foo bar more; then
     ...
   fi

CategoryShell

-  ⇤ ← Revision 11 as of 2012-04-29 23:44:04 → 
  Size: 487
  Editor: ormaaj
  Comment: rm old comments, rm regex examples because they're stupid and pointless, add category
+   ← Revision 12 as of 2013-01-03 17:46:44 → ⇥
  Size: 838
  Editor: static-74-106-235-64
  Comment:
-Deletions are marked like this.
+Additions are marked like this.
 Line 21:
+Alternatively, the "inarray" function could be used:
{{{
   # usage: inarray NEEDLE HAYSTACK ...
   # returns 0 if NEEDLE is in HAYSTACK, otherwise 1.
   inarray() {
     local n=$1 h
     shift

     for n; do
       [[ $n = "$h" ]] && return
     done
     return 1
   }

   if inarray $var foo bar more; then
     ...
   fi
}}}