Diff for "BashFAQ/066"

Differences between revisions 1 and 3 (spanning 2 versions)

I want to check if [[ $var == foo || $var == bar || $var == more ]] without repeating $var n times.

Here's a portable solution:

   case $var in
      foo|bar|more) ... ;;
   esac

And here's one that uses =~ (which requires bash 3.0 or higher). This only works in bash 3.1, not in bash 3.2 (and is untested in 3.0):

   if [[ $var =~ '^(foo|bar|more)$' ]]; then
      ...
   fi

I'd just stick with the case, myself. --GreyCat

-  ⇤ ← Revision 1 as of 2007-05-03 00:00:48 → 
  Size: 191
  Editor: redondos
  Comment:
+   ← Revision 3 as of 2007-05-24 15:17:19 → ⇥
  Size: 496
  Editor: GreyCat
  Comment: =~ example was wrong.  very wrong.  and is still mostly wrong.
-Deletions are marked like this.
+Additions are marked like this.
 Line 2:
-== I want to check if [[ $var == foo || $var == bar || $var = more ]] without repeating $var n times. ==
+== I want to check if [[ $var == foo || $var == bar || $var == more ]] without repeating $var n times. ==
 Line 4:
+Here's a portable solution:
-Line 9:
+Line 10:
+And here's one that uses `=~` (which requires bash 3.0 or higher).  This '''only works in bash 3.1''', not in bash 3.2 (and is untested in 3.0):
{{{
   if [[ $var =~ '^(foo|bar|more)$' ]]; then
      ...
   fi
}}}

I'd just stick with the `case`, myself. --GreyCat