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| Hello, im from Gergia. It has been two years of agonising pain and incredible hard work but YOU'VE DONE IT! We are all very proud of you and the way that you have used your terrible accident to help others who have found themselves amputees antique style handheld mirror Perfect site, i like it! http://diamonds83.free-site-host.com/ latest female fashion tre, see you | <<Anchor(faq19)>> == How can I split a file into line ranges, e.g. lines 1-10, 11-20, 21-30? == Some Unix systems provide the {{{split}}} utility for this purpose: {{{#!highlight bash split --lines 10 --numeric-suffixes input.txt output- }}} For more flexibility you can use {{{sed}}}. The {{{sed}}} command can print e.g. the line number range 1-10: {{{#!highlight bash sed -n -e '1,10p' -e '10q' }}} This stops {{{sed}}} from printing each line ({{{-n}}}). Instead it only processes the lines in the range 1-10 ("1,10"), and prints them ("p"). The command will quit after reading line 10 ("10q"). We can now use this to print an arbitrary range of a file (specified by line number): {{{#!highlight bash # POSIX shell file=/etc/passwd range=10 cur=1 last=$(wc -l < "$file") # count number of lines chunk=1 while [ $cur -lt $last ] do endofchunk=$(($cur + $range - 1)) sed -n -e "$cur,${endofchunk}p" -e "${endofchunk}q" "$file" > chunk.$(printf %04d $chunk) chunk=$(($chunk + 1)) cur=$(($cur + $range)) done }}} The previous example uses POSIX [[ArithmeticExpression|arithmetic]], which older [[BourneShell|Bourne shells]] do not have. In that case the following example should be used instead: {{{#!highlight bash # legacy Bourne shell; assume no printf either file=/etc/passwd range=10 cur=1 last=`wc -l < "$file"` # count number of lines chunk=1 while test $cur -lt $last do endofchunk=`expr $cur + $range - 1` sed -n -e "$cur,${endofchunk}p" -e "${endofchunk}q" "$file" > chunk.$chunk chunk=`expr $chunk + 1` cur=`expr $cur + $range` done }}} Awk can also be used to produce a more or less equivalent result: {{{#!highlight bash awk -v range=10 '{print > FILENAME "." (int((NR -1)/ range)+1)}' file }}} |
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| CategoryHomepage | CategoryShell |
How can I split a file into line ranges, e.g. lines 1-10, 11-20, 21-30?
Some Unix systems provide the split utility for this purpose:
Toggle line numbers
1 split --lines 10 --numeric-suffixes input.txt output-
For more flexibility you can use sed. The sed command can print e.g. the line number range 1-10:
Toggle line numbers
1 sed -n -e '1,10p' -e '10q'
This stops sed from printing each line (-n). Instead it only processes the lines in the range 1-10 ("1,10"), and prints them ("p"). The command will quit after reading line 10 ("10q").
We can now use this to print an arbitrary range of a file (specified by line number):
Toggle line numbers
1 # POSIX shell
2 file=/etc/passwd
3 range=10
4 cur=1
5 last=$(wc -l < "$file") # count number of lines
6 chunk=1
7 while [ $cur -lt $last ]
8 do
9 endofchunk=$(($cur + $range - 1))
10 sed -n -e "$cur,${endofchunk}p" -e "${endofchunk}q" "$file" > chunk.$(printf %04d $chunk)
11 chunk=$(($chunk + 1))
12 cur=$(($cur + $range))
13 done
The previous example uses POSIX arithmetic, which older Bourne shells do not have. In that case the following example should be used instead:
Toggle line numbers
1 # legacy Bourne shell; assume no printf either
2 file=/etc/passwd
3 range=10
4 cur=1
5 last=`wc -l < "$file"` # count number of lines
6 chunk=1
7 while test $cur -lt $last
8 do
9 endofchunk=`expr $cur + $range - 1`
10 sed -n -e "$cur,${endofchunk}p" -e "${endofchunk}q" "$file" > chunk.$chunk
11 chunk=`expr $chunk + 1`
12 cur=`expr $cur + $range`
13 done
Awk can also be used to produce a more or less equivalent result:
Toggle line numbers
1 awk -v range=10 '{print > FILENAME "." (int((NR -1)/ range)+1)}' file