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-<<Anchor(faq19)>>
== How can I split a file into line ranges, e.g. lines 1-10, 11-20, 21-30? ==
Some Unix systems provide the {{{split}}} utility for this purpose:

{{{
    split --lines 10 --numeric-suffixes input.txt output-
}}}

For more flexibility you can use {{{sed}}}.  The {{{sed}}} command can print e.g. the line number range 1-10:
{{{
    sed -n -e '1,10p' -e '10q'
}}}

This stops {{{sed}}} from printing each line ({{{-n}}}). Instead it only processes the lines in the range 1-10 ("1,10"), and prints them ("p"). The command will quit after reading line 10 ("10q").

We can now use this to print an arbitrary range of a file (specified by line number):

{{{
# POSIX shell
file=/etc/passwd
range=10
cur=1
last=$(wc -l < "$file") # count number of lines
chunk=1
while [ $cur -lt $last ]
do
    endofchunk=$(($cur + $range - 1))
    sed -n -e "$cur,${endofchunk}p" -e "${endofchunk}q" "$file" > chunk.$(printf %04d $chunk)
    chunk=$(($chunk + 1))
    cur=$(($cur + $range))
done
}}}

The previous example uses POSIX [[ArithmeticExpression|arithmetic]], which older [[BourneShell|Bourne shells]] do not have. In that case the following example should be used instead:

{{{
# legacy Bourne shell; assume no printf either
file=/etc/passwd
range=10
cur=1
last=`wc -l < "$file"` # count number of lines
chunk=1
while test $cur -lt $last
do
    endofchunk=`expr $cur + $range - 1`
    sed -n -e "$cur,${endofchunk}p" -e "${endofchunk}q" "$file" > chunk.$chunk
    chunk=`expr $chunk + 1`
    cur=`expr $cur + $range`
done
}}}

Awk can also be used to produce a more or less equivalent result:

{{{
 awk -v range=10 '{print > FILENAME "." (int((NR -1)/ range)+1)}' file
}}}
+Nice page ;) Thanks for sharing the world your story, thank you for reminding me that life must go on no matter what ice cream Hope it will always be alive! http://saverhl.wordpress.com/tag/coffee/ tea,  I love it :) Respect !