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How can I print the n'th line of a file?
The dirty (but not quick) way would be:
sed -n ${n}p "$file"but this reads the whole input file, even if you only wanted the third line.
This one avoids that problem:
sed -n "$n{p;q;}" "$file"At line $n the command "p" is run, printing it, with a "q" afterwards: quit the program.
Another way, more obvious to some, is to grab the last line from a listing of the first n lines:
head -n $n $file | tail -n 1
Another approach, using AWK:
awk "NR==$n{print;exit}" fileIf you want more than one line, it's pretty easy to adapt any of the previous methods:
x=3 y=4
sed -n "$x,${y}p;${y}q;" "$file" # Print lines $x to $y; quit after $y.
head -n $y "$file" | tail -n $(($y - $x + 1)) # Same
awk "NR>=$x{print} NR==$y{exit}" "$file" # Same