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Comment: Added example showing the use of find's -empty option
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''I just deleted three completely '''wrong''' answers from this question. Please, people, make sure that when you add to the FAQ, your answers'' * answer the question that was asked, and * actually '''work''' ''Thanks. -- GreyCat'' Most modern systems have an "ls -A" which explicitly omits "." and ".." from the directory listing: |
In Bash, you can do this safely and easily with the `nullglob` and `dotglob` options (which change the behaviour of [[glob|globbing]]), and [[BashFAQ/005|arrays]]: |
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if [ -n "$(ls -A somedir)" ] then echo directory is non-empty |
# Bash shopt -s nullglob dotglob files=(*) (( ${#files[*]} )) || echo directory is empty shopt -u nullglob dotglob }}} Or you can pour it into a SubShell to avoid having to reset (in fact, unset! - the code above assumes the shell options were unset before) the shell options again: {{{ # Bash if (shopt -s nullglob dotglob; f=(*); ((! ${#f[@]}))); then echo "The current directory is empty." |
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Of course, you can use any glob you like instead of `*`. E.g. `*.mpg` or `/my/music/*.mpg` works fine. | |
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This can be shortened to: | Some people dislike `nullglob` because having unmatched globs vanish altogether confuses programs like `ls`. Mistyping `ls *.zip` as `ls *.zpi` may cause every file to be displayed. Setting `nullglob` in a SubShell avoids accidentally changing its setting in the rest of the shell, at the price of an extra `fork()`. If your script needs to run with various non-Bash shell implementations, you can try using an external program like python, perl, or find; or you can try one of these: |
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if [ "$(ls -A somedir)" ] then echo directory is non-empty |
# POSIX # Clobbers the positional parameters, so make sure you don't need them. set -- * if test -e "$1" || test -L "$1"; then echo "directory is non-empty" |
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Another way, using Bash features, involves setting a special shell option which changes the behavior of [:glob:globbing]. Some people prefer to avoid this approach, because it's so drastically different and could severely alter the behavior of scripts. Nevertheless, if you're willing to use this approach, it does greatly simplify this particular task: |
(The `-L` test is required because `-e` fails if the first file is a [[BashFAQ/097|dangling symlink]].) |
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shopt -s nullglob if [[ -z $(echo *) ]]; then echo directory is empty |
# Bourne # (Of course, the system must have printf(1).) if test "`printf '%s %s %s' .* *`" = '. .. *' && test ! -f '*' then echo "directory is empty" |
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shopt -u nullglob | |
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Yes, they're quite ugly, but they should be more portable than anything depending on [[ParsingLs|ls output]]. Even `ls -A` solutions can break (e.g. on HP-UX, if you are root, `ls -A` does the exact ''opposite'' of what it does if you're not root -- and no, I can't make up something that incredibly stupid). | |
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This can also be combined with Bash's [:BashFAQ/005:arrays]. The major advantage here is that you probably wanted to ''do'' something with all the files, so having them loaded into an array is something that will help you with the overall task: | In fact, you may wish to avoid the ''direct'' question altogether. Usually people want to know whether a directory is empty ''because'' they want to do something involving the files therein, etc. Look to the larger question. For example, one of these [[UsingFind|find-based examples]] may be an appropriate solution: |
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shopt -s nullglob files=(*) (( ${#files[*]} )) || echo directory is empty shopt -u nullglob |
# Bourne find "$somedir" -type f -exec echo Found unexpected file {} \; find "$somedir" -maxdepth 0 -empty -exec echo {} is empty. \; # GNU/BSD find "$somedir" -type d -empty -exec cp /my/configfile {} \; # GNU/BSD |
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`nullglob` also simplifies various other operations: |
Most commonly, all that's really needed is something like this: |
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shopt -s nullglob for i in *.zip; do blah blah "$i" # No need to check $i is a file. done shopt -u nullglob }}} Without the {{{nullglob}}}, that would have to be: {{{ for i in *.zip; do [[ -f $i ]] || continue # If no .zip files, i becomes *.zip blah blah "$i" |
# Bourne for f in ./*.mpg; do test -f "$f" || continue mympgviewer "$f" |
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In other words, the person asking the question may have ''thought'' an explicit empty-directory test was needed to avoid an error message like `mympgviewer: ./*.mpg: No such file or directory` when in fact no such test is required. | |
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(You may want to use the latter anyway, if there's a possibility that the glob may match directories in addition to files.) Finally, you may wish to avoid the ''direct'' question altogether. Usually people want to know whether a directory is empty... ''because'' they want to do something involving the files therein, etc. Look to the larger question. For example, something like this may be appropriate solutions: {{{ find "$somedir" -type d -empty -exec echo "$somedir is empty." find "$somedir" -type f -exec echo Found unexpected file {} \; }}} It's all a matter of addressing the program's actual requirements. |
---- CategoryShell |
How can I check whether a directory is empty or not? How do I check for any *.mpg files?
In Bash, you can do this safely and easily with the nullglob and dotglob options (which change the behaviour of globbing), and arrays:
# Bash shopt -s nullglob dotglob files=(*) (( ${#files[*]} )) || echo directory is empty shopt -u nullglob dotglob
Or you can pour it into a SubShell to avoid having to reset (in fact, unset! - the code above assumes the shell options were unset before) the shell options again:
# Bash if (shopt -s nullglob dotglob; f=(*); ((! ${#f[@]}))); then echo "The current directory is empty." fi
Of course, you can use any glob you like instead of *. E.g. *.mpg or /my/music/*.mpg works fine.
Some people dislike nullglob because having unmatched globs vanish altogether confuses programs like ls. Mistyping ls *.zip as ls *.zpi may cause every file to be displayed. Setting nullglob in a SubShell avoids accidentally changing its setting in the rest of the shell, at the price of an extra fork().
If your script needs to run with various non-Bash shell implementations, you can try using an external program like python, perl, or find; or you can try one of these:
# POSIX # Clobbers the positional parameters, so make sure you don't need them. set -- * if test -e "$1" || test -L "$1"; then echo "directory is non-empty" fi
(The -L test is required because -e fails if the first file is a dangling symlink.)
# Bourne # (Of course, the system must have printf(1).) if test "`printf '%s %s %s' .* *`" = '. .. *' && test ! -f '*' then echo "directory is empty" fi
Yes, they're quite ugly, but they should be more portable than anything depending on ls output. Even ls -A solutions can break (e.g. on HP-UX, if you are root, ls -A does the exact opposite of what it does if you're not root -- and no, I can't make up something that incredibly stupid).
In fact, you may wish to avoid the direct question altogether. Usually people want to know whether a directory is empty because they want to do something involving the files therein, etc. Look to the larger question. For example, one of these find-based examples may be an appropriate solution:
# Bourne find "$somedir" -type f -exec echo Found unexpected file {} \; find "$somedir" -maxdepth 0 -empty -exec echo {} is empty. \; # GNU/BSD find "$somedir" -type d -empty -exec cp /my/configfile {} \; # GNU/BSD
Most commonly, all that's really needed is something like this:
# Bourne for f in ./*.mpg; do test -f "$f" || continue mympgviewer "$f" done
In other words, the person asking the question may have thought an explicit empty-directory test was needed to avoid an error message like mympgviewer: ./*.mpg: No such file or directory when in fact no such test is required.