Differences between revisions 1 and 3 (spanning 2 versions)
Revision 1 as of 2007-05-03 00:00:48
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Editor: redondos
Comment:
Revision 3 as of 2007-05-24 15:17:19
Size: 496
Editor: GreyCat
Comment: =~ example was wrong. very wrong. and is still mostly wrong.
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== I want to check if [[ $var == foo || $var == bar || $var = more ]] without repeating $var n times. == == I want to check if [[ $var == foo || $var == bar || $var == more ]] without repeating $var n times. ==
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Here's a portable solution:
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And here's one that uses `=~` (which requires bash 3.0 or higher). This '''only works in bash 3.1''', not in bash 3.2 (and is untested in 3.0):
{{{
   if [[ $var =~ '^(foo|bar|more)$' ]]; then
      ...
   fi
}}}

I'd just stick with the `case`, myself. --GreyCat

Anchor(faq66)

I want to check if [[ $var == foo || $var == bar || $var == more ]] without repeating $var n times.

Here's a portable solution:

   case $var in
      foo|bar|more) ... ;;
   esac

And here's one that uses =~ (which requires bash 3.0 or higher). This only works in bash 3.1, not in bash 3.2 (and is untested in 3.0):

   if [[ $var =~ '^(foo|bar|more)$' ]]; then
      ...
   fi

I'd just stick with the case, myself. --GreyCat

BashFAQ/066 (last edited 2015-06-20 07:58:04 by ormaaj)