How can I get the newest (or oldest) file from a directory?

This page should be merged with BashFAQ/003

The intuitive answer of ls -t | head -1 is wrong, because parsing the output of ls is unsafe; instead, you should create a loop and compare the timestamps:

# Bash
files=(*) newest=${files[0]}
for f in "${files[@]}"; do
  if [[ $f -nt $newest ]]; then
    newest=$f
  fi
done

Then you'll have the newest file (according to modification time) in $newest. To get the oldest, simply change -nt to -ot (see help test for a list of operators), and of course change the names of the variables to avoid confusion.

Bash has no means of comparing file timestamps other than mtime, so if you wanted to get (for example) the most-recently-accessed file (newest by atime), you would have to get some help from the external command stat(1) (if you have it) or the loadable builtin finfo (if you can load builtins).

Here's an example using stat from GNU coreutils 6.10 (sadly, even across Linux systems, the syntax of stat is not consistent) to get the most-recently-accessed file. (In this version, %X is the last access time.)

# Bash, GNU coreutils
newest= newest_t=0
for f in *; do
  t=$(stat --format=%X -- "$f")   # atime
  if ((t > newest_t)); then
    newest_t=$t
    newest=$f
  fi
done

This also has the disadvantage of spawning an external command for every file in the directory, so it should be done this way only if necessary. To get the oldest file using this technique, you'd either have to initialize oldest_t with the largest possible timestamp (a tricky proposition, especially as we approach the year 2038), or with the timestamp of the first file in the directory, as we did in the first example.

Here is another solution spawning an external command, but posix:

# posix
unset newest
for f in ./*; do
  # set the newest during the first iteration
  newest=${newest-$f} 
  #-prune to avoid descending in the directories, the exit status of find is useless here, we check the output
  if [ "$(find "$f" -prune -newer "$newest")" ]; then 
    newest=$f
  fi
done

Example: how to remove all but the most recent directory. (Note, the modification time on a directory is the time of the most recent operation which changes that directory -- meaning the last file creation, file deletion, or file rename.)

 $ cat clean-old 
 dirs=(enginecrap/*/) newest=${dirs[0]}
 for d in "${dirs[@]}"
  do if [[ $d -nt $newest ]]
     then newest=$d
     fi
  done

 for z in "${dirs[@]}"
  do if [[ "$z" != "$newest" ]]
     then rm -rf "$z"
     fi
  done
 $ for x in 20101022 20101023 200101025 20101107 20101109; do mkdir enginecrap/"$x";done
 $ ls enginecrap/
 200101025       20101022        20101023        20101107        20101109
 $ ./clean-old 
 $ ls enginecrap/
 20101109


CategoryShell

BashFAQ/099 (last edited 2013-03-18 21:54:17 by geirha)